Diagonal Sum

A set of numbers forming a matrix N*N is passed as input. The program has to print the sum of numbers along the diagonals. 

Input Format: The first line will contain the value of N. The next N lines will contain N numbers each separated by one or more spaces. 

Boundary Conditions: 2 <= N <= 10 Value of a given number in the matrix is from 0 to 99999999. 

Output Format: The sum of the numbers along the diagonals. 

Example Input/Output 1:

Input: 

3 

5 6 7 

8 9 1 

2 3 4 

Output: 

27 

Explanation: The sum of the numbers along the diagonal = 5+9+4+7+2 = 27. Please pay attention in not counting the overlapping number 9 (which is in the middle) twice. 

Example Input/Output 2: 

Input: 

4 

2 3 4 5 

1 5 3 2 

3 3 9 8 

9 7 6 5 

Output: 

41 

Explanation: The sum of the numbers along the diagonal = 2+5+9+5+5+3+3+9 = 41

Source Code:

n=int(input())

m=[[int(i) for i in input().split()]for j in range(n)]

s=sum(m[i][i] for i in range(n))

s1=sum(m[i][n-i-1] for i in range(n))

if n%2!=0:

    print(s+s1-m[n//2][n//2])

else:

    print(s+s1)