Pattern Printing N - Sequence 001 - C,Java

The program must accept an integer N and print the pattern as shown in the Example Input/Output. 

Input Format: The first line contains N. 

Output Format: N lines containing the pattern as shown in the Example Input/Output. 

Boundary Conditions: 

2 <= N <= 100 

Example Input/Output 1: 

Input:
4 

Output:

1 2 3 4 

9 10 11 12 

13 14 15 16 

5 6 7 8 

Example Input/Output 2: 

Input: 

7 

Output: 

1 2 3 4 5 6 7 

15 16 17 18 19 20 21 

29 30 31 32 33 34 35 

43 44 45 46 47 48 49 

36 37 38 39 40 41 42 

22 23 24 25 26 27 28 

8 9 10 11 12 13 14

Source Code:

C:

#include<stdio.h>

#include <stdlib.h>

int main()

{

int n,c=1,i,j,k=0,m=0;

scanf("%d",&n);

int a[n][n];

for(i=0;i<n;i++)

{

    if(i%2==0)

    {

        for(j=0;j<n;j++)

        {

            printf("%d ",c);

            c++;

        }

        printf("\n");

    }

    else

    {

        for(j=0;j<n;j++)

        {

            if(m==n)

            m=0;

            a[k][m]=c;

            c++;

            m++;

        }

        k++;

    }

}

for(i=k-1;i>=0;i--)

{

    for(j=0;j<m;j++)

        printf("%d ",a[i][j]);

    printf("\n");

}

}

JAVA:

import java.util.*;
public class Hello {

    public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int m=1,i,j,o;
o=n%2==0?n:n+1;
for(i=0;i<n;i++)
{
   for(j=m;j<m+n;j++)
        System.out.print(j+" ");
   System.out.println();
   if(i==(o/2)-1)
      m+=(n%2==0)?n:(-1*n);
   else if(i<(o/2)-1)
      m+=2*n;
   else
      m-=2*n;
}
}

}