Print Odd Even Negative Integer Count-python,c

Accept N integers and print the count of odd, even and negative integer count as the output.

Input Format:
The first line contains N.
The second line contains N integer values, separated by space.

Output Format:
The first line contains the count of odd, even and negative integer count separated by a space.

Boundary Conditions:
1 <= N <= 1000

Example Input/Output 1:
Input:
10
78 20 4 -12 96 93 15 60 -58 22

Output:
2 6 2

Example Input/Output 2:
Input:
20
-16 -32 87 79 -33 7 -8 87 63 25 84 39 -20 -12 84 98 8 28 22 74

Output:
7 7 6

Python code:

n,neg,odd,eve,m=int(input()),0,0,0,[int(i) for i in input().split()]

for i in m:

    if i<0:

        neg+=1

    elif i%2==0 :

        eve+=1

    else:

        odd+=1

print("{0} {1} {2}".format(odd,eve,neg))  

C Code:

#include<stdio.h>
int main()
{
int n,i,e=0,o=0,ne=0;
scanf("%d",&n);
int a[n];
for(i=0;i<n;i++){
    scanf("%d",&a[i]);
if(a[i]<0) ne++;
else if(a[i]%2==0&&a[i]>=0) e++;
else o++;
}
    printf("%d %d %d",o,e,ne);

}

Java code:                                                   // coded by ~thamo

import java.util.*;
public class Hello {

    public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int a,o=0,e=0,u=0;
for(int i=1;i<=n;i++)
{
a=sc.nextInt();
if(a<0)
u++;
else if(a&1==1)
o++;
else
e++;
}
     System.out.print(o+" "+e+" "+u+" ");
}

}