Restaurant - Lucky Numbers Discount -python,c++

Every day in a restaurant two numbers X and Y are considered lucky numbers. 

If the bill amount B is divisible by X, then X% discount is offered.

If the bill amount B is divisible by Y, then Y% discount is offered. 

If the bill amount B is divisible by both X and Y, then no amount is to be paid.  

The program must accept X, Y and B and print the amount to be paid as the output (precision is upto 3 decimal places) 

Input Format:

The first line contains B The second line contains X The third line contains Y 

Output Format:

The first line contains the amount to be paid finally after discount. 

Boundary Conditions: 

• 1 <= X,Y <= 50 
• 20 <= B <= 100000

Example Input/Output 1:

Input:

500

20

50 

Output:

0.000 

Example Input/Output 2:

Input:

100

9

10 

Output:

90.000

  
python:

m,b,n=int(input()),int(input()),int(input())

if m%b==0 and m%n==0:

    print("0.000")

elif m%n==0:

    print("%.3f"%(m-m*(n/100)))

elif m%b==0:

    print("%.3f"%(m-m*(b/100)))

else:

    print("%.3f"%(m))

c++:                                                         // coded by thamodar

#include <iostream>

#include<iomanip>

using namespace std;

int main(int argc, char** argv)

{

int b,x,y;                                                          //  b as bill number

float d;

cin>>b>>x>>y;

if(b%x==0 && b%y==0)

d=0;

else if(b%x==0)

d=b-(b*x*.01);

else if(b%y==0)

d=b-(b*y*.01);

else

d=b;

cout<<fixed<<setprecision(3)<<d;

}