Numbers Addition - Left to Right - c

Given two numbers N1 and N2, find the sum by adding them from left to right.

Input Format:

 The first line contains N1.

The second line contains N2.

Output Format:

The first line contains the sum of N1 and N2 added from left to right.

Boundary Conditions: 100 <= N1 <= 999999 100 <= N2 <= 999999

Example Input/Output 1:

Input:

6321

5235

Output:

1656

Example Input/Output 2:

Input:

16282

5964

Output:

11257

Solution:

#include<stdio.h>

#include <stdlib.h>

int main()

{

int a,b;

scanf("%d%d",&a,&b);

int p=rev(a);

int c=rev(b);

counts(&p,&c);

int r=p+c;

printf("%d",rev(r));

return 0;

}

int rev(int a){

    int t=0;

    while(a>0){

        t=t*10+a%10;

        a=a/10;

    }

    return t;

}

int counts(int *a,int *b){

          if(count(*a)==count(*b)){

                   return 1;

          }

          else if(count(*a)>count(*b)){

                   int v=count(*a)-count(*b);

                   while(v--){

                   *b=*b*10;

          }

          }

          else{

          int d=count(*b)-count(*a);

          while(d--){

          *a=*a*10;

}

}

}

int count(int a){

          int c=0;

          while(a>0){

          a=a/10;

          c++;

}

return c;

}